Electric Circuits
When a parallel-plate capacitor with air between the plates is connected to a battery and fully charged, if the space between the plates is then filled with a dielectric material, how does this affect the electric field between the plates?
The electric field remains unchanged as it only depends on plate separation and charge.
The electric field increases because the dielectric adds extra charge carriers.
The electric field decreases because the dielectric reduces the effective voltage across the plates.
The electric field reverses direction due to polarization of the dielectric molecules.
A long, straight wire carries a steady current I and is bent into a semicircular loop of radius R; if the magnetic field at the center of curvature of the loop is , what would be the magnetic field at this point if the wire were instead shaped into a full circular loop carrying the same current?
Zero
2B
B
B/2
Which component in an electric circuit is used primarily to store charge?
Transformer.
Resistor.
Capacitor.
Inductor.
A parallel-plate capacitor initially connected to a battery remains connected after inserting a dielectric material completely filling space between plates; how does this affect its electric field?
It stays the same despite the introduction of a new medium capable of altering local permittivity values since the capacitors were already fully charged prior to the addition of the third substance/middle layer, etcetera.
It decreases because the dielectric increases capacitance without affecting total charge supplied by the battery.
It becomes zero all of a sudden upon the placement of the intermediary region filled with a particular type of molecular arrangement, opposed to the empty state it previously held.
It increases since dielectrics typically have higher permittivity than vacuum/air, making them better conductors, thus enhancing the fields present during the initial charging process before the insertion took place.
Which statement correctly describes the effect increasing distance between two charges has on the electrostatic force they experience according to Coulomb's Law?
The electrostatic force decreases since force is proportional to the inverse square of the distance between charges.
The electrostatic force remains unchanged as it is directly proportional to the product of the charges' magnitudes.
The electrostatic force increases because force is inversely proportional to the square of the distance between charges.
The electrostatic force decreases linearly with distance once a certain threshold distance is surpassed.
What is the result when the divergence of an electric field is calculated in a region with no charge present?
A constant value, indicating a uniform electric field.
Negative, implying the presence of negative charges.
Positive, implying the presence of positive charges.
Zero, as there are no sources or sinks of the field.
In an LRC series circuit with resonance frequency , if both resistance and capacitance are doubled, how does the new resonance frequency compare to ?
f' = 2 * f_0
f' = f_0
f' = f_0/√2
f' = √2 * f_0

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How does increasing the separation between two point charges affect the magnitude of force they exert on each other according to Coulomb's law?
It decreases as an inverse square of their separation distance.
It decreases linearly with their separation distance.
It increases proportionally with their separation distance.
It remains constant regardless of their separation distance.
How is an electric field (E) related to the force (F) experienced by a test charge (q)?
What happens to the magnitude of the electric field strength when the source charge density increases in a given region?
The magnitude remains constant as it depends solely on the geometry of the space.
The magnitude decreases since higher charge density leads to mutual repulsion weakening the field.
The magnitude increases since stronger charge density creates stronger electric fields.
The magnitude is inversely proportional to charge density due to the inverse square law.