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Logarithmic Function Manipulation

Alice White

Alice White

8 min read

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Study Guide Overview

This study guide covers logarithmic function manipulation, focusing on the relationship between logarithmic and exponential functions. Key properties include the Product, Power, and Change of Base rules, along with their graphical interpretations. It also emphasizes natural logarithms (ln) and their relationship to e. Finally, the guide provides practice questions and exam tips covering simplifying expressions, solving equations, graphing, and applications of logarithms.

AP Pre-Calculus: Logarithmic Function Properties - The Night Before 🌠

Hey there! Let's get you feeling confident about logarithmic functions. Remember, they're just the inverse of exponential functions, so if you're comfy with those, this will be a breeze! Let's dive in!

2.12 Logarithmic Function Manipulation

Quick Recap ⏰

  • Logarithmic functions are inverses of exponential functions. They "undo" exponential operations.
  • Just like exponential functions, logarithmic functions have properties that allow us to simplify, solve, and model equations.
Memory Aid

Think of logs as "exponent finders." If by=xb^y = x, then logb(x)=y\log_b(x) = y. This helps remember the relationship between exponential and log functions.

Properties of Logarithmic Functions 🧮

Let's explore the key properties that'll help you ace those exam questions!

Key Concept

✖️ Product Property

  • Concept: The log of a product is the sum of the logs.
  • Formula: logb(xy)=logb(x)+logb(y)\log_b(xy) = \log_b(x) + \log_b(y)
  • In Simple Terms: When you multiply inside a log, you can split it into the sum of two logs.
Exam Tip

This property is super useful for expanding logarithmic expressions and can help simplify complex equations.

  • Graphical Interpretation: A horizontal dilation (stretch/compression) of a log function is equivalent to a vertical translation (shift up/down).
    • f(x)=logb(kx)f(x) = \log_b(kx) is equivalent to f(x)=logb(k)+logb(x)=a+logb(x)f(x) = \log_b(k) + \log_b(x) = a + \log_b(x), where a=logb(k)a = \log_b(k).

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The product property in action: Notice how multiplying the input (x) by 2 results in a vertical shift of the graph.

🦸🏽 Power Property

  • Concept: The log of a number raised to a power is the power times the log of the number.
  • Formula: logb(xn)=nlogb(x)\log_b(x^n) = n\log_b(x)
  • In Simple Terms: When you have an exponent inside a log, you can bring it down as a multiplier.
Exam Tip

This property is essential for solving logarithmic equations where the variable is in the exponent.

  • Graphical Interpretation: Raising the input of a log function to a power results in a vertical dilation of the graph.
    • f(x)=logb(xk)f(x) = \log_b(x^k) results in a vertical stretch or compression.

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The power property: Notice how the exponent of the input (x) becomes a multiplier of the log function.

Common Mistake

Remember, the power property only applies when the entire input of the log is raised to a power, not just part of it. For example, logb(x2y)2logb(xy)\log_b(x^2y) ≠ 2\log_b(xy).

CNX_Precalc_Figure_04_04_0142.jpg

Visualizing the power property: The graph of f(x)=2log4(x)f(x) = 2\log_4(x) is a vertical stretch of y=log4(x)y = \log_4(x).

🔄 Change of Base Property

  • Concept: Allows you to convert a log from one base to another.
  • Formula: logb(x)=loga(x)loga(b)\log_b(x) = \frac{\log_a(x)}{\log_a(b)}
  • In Simple Terms: Change the base of a log by dividing by the log of the old base with the new base.
Quick Fact

This property is super useful when your calculator doesn't have a specific base log function (like log base 5). Use common log (base 10) or natural log (base e) instead.

change-of-base-formula.png

The change of base formula: This formula allows you to calculate logarithms with any base using a calculator that only has base 10 or base e logarithms.

  • Graphical Interpretation: All log functions are vertical dilations of each other. Changing the base affects the "height" of the graph.

Natural Logs and e 🌿

  • Definition: The natural logarithm, denoted as ln(x)\ln(x), is the logarithm with base e, where e ≈ 2.71828. - Relationship: ln(x)=loge(x)\ln(x) = \log_e(x)
  • Inverse: ln(x)\ln(x) is the inverse of exe^x.
Key Concept

The natural log is super important in calculus and many applications. Get comfortable with it!

  • Domain: All positive real numbers.
  • Range: All real numbers.

common-natural-logs.png

Comparing common and natural logarithms: Notice the difference in the base and how it affects the graph.

Final Exam Focus 🎯

High-Priority Topics

  • Product, Power, and Change of Base Properties: Know these inside and out! They're fundamental for solving equations and simplifying expressions.
  • Natural Logarithms: Understand their properties and how they relate to exponential functions.
  • Graphical Transformations: Be able to relate the algebraic properties to changes in the graph of a log function.

Common Question Types

  • Simplifying Logarithmic Expressions: Use the properties to combine or expand logs.
  • Solving Logarithmic Equations: Apply properties to isolate the variable.
  • Graphing Logarithmic Functions: Understand how transformations affect the graph.
  • Applications: Solve real-world problems using logarithmic models.

Last-Minute Tips

  • Time Management: Don't spend too long on one question. Move on and come back if you have time.
  • Common Pitfalls: Be careful with the order of operations and applying properties correctly.
  • Strategies: If you're stuck, try rewriting the problem using a different property or a different base.

Practice Question

Practice Questions

Multiple Choice Questions

  1. Simplify the expression: log2(16x3)\log_2(16x^3) (A) 4+3log2(x)4 + 3\log_2(x) (B) 4log2(x)4\log_2(x) (C) 16+3log2(x)16 + 3\log_2(x) (D) 4+log2(x3)4 + \log_2(x^3)

  2. Solve for x: log3(x2)=4\log_3(x^2) = 4 (A) 2 (B) 9 (C) 81 (D) 3

  3. Which expression is equivalent to log5(25)+log5(125)\log_5(25) + \log_5(125)? (A) log5(150)\log_5(150) (B) log5(3125)\log_5(3125) (C) 55 (D) 77

Free Response Question

Consider the function f(x)=2ln(x+3)1f(x) = 2\ln(x+3) - 1.

(a) State the domain of f(x)f(x). (b) Find the x-intercept of f(x)f(x). (c) Describe the transformations applied to the graph of y=ln(x)y = \ln(x) to obtain the graph of f(x)f(x). (d) Sketch the graph of f(x)f(x), labeling at least one key point.

Scoring Breakdown:

(a) [1 point] - 1 point for stating the correct domain: x>3x > -3 or (3,)(-3, \infty)

(b) [2 points] - 1 point for setting f(x)=0f(x) = 0 and attempting to solve for x. - 1 point for the correct x-intercept: x=e1/23x = e^{1/2} - 3 or approximately -1.35

(c) [3 points] - 1 point for vertical stretch by a factor of 2. - 1 point for horizontal shift to the left by 3 units. - 1 point for vertical shift down by 1 unit.

(d) [2 points] - 1 point for a graph with the correct general shape of a logarithmic function. - 1 point for labeling a key point (e.g., x-intercept or a point from the domain).

Answers

Multiple Choice:

  1. (A) 4+3log2(x)4 + 3\log_2(x)
  2. (B) 9
  3. (C) 5

Free Response:

(a) Domain: x>3x > -3 or (3,)(-3, \infty)

(b) Set f(x)=0f(x) = 0: 2ln(x+3)1=02\ln(x+3) - 1 = 0. Solve for x: x=e1/23x = e^{1/2} - 3

(c) The graph of y=ln(x)y = \ln(x) is vertically stretched by a factor of 2, horizontally shifted to the left by 3 units, and vertically shifted down by 1 unit.

(d) Sketch of the graph should show a log function with the correct transformations (e.g., a point around (-2, -1) and x-intercept at e1/23e^{1/2} - 3 )

You've got this! Remember to breathe and trust your preparation. You're ready to rock this exam! 🎉

Question 1 of 11

If by=xb^y = x, which of the following is the equivalent logarithmic form? 🚀

y=logx(b)y = \log_x(b)

x=logb(y)x = \log_b(y)

y=logb(x)y = \log_b(x)

b=logy(x)b = \log_y(x)