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Setting Up a Chi Square Goodness of Fit Test

Ava Garcia

Ava Garcia

8 min read

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Study Guide Overview

This guide covers chi-square tests, focusing on the goodness-of-fit (GOF) test. It explains expected counts, the chi-square statistic, chi-square distributions, and degrees of freedom. The guide also details GOF test conditions (random, independence, large counts), provides example problems and practice questions, and offers exam tips.

AP Statistics: Chi-Square Tests - Your Ultimate Study Guide ๐Ÿš€

Hey there, future AP Stats superstar! Let's get you prepped and confident for the exam with this super-focused guide on Chi-Square tests. We'll break down the concepts, highlight key points, and make sure you're ready to ace it!

Expected Counts: What to Expect? ๐Ÿค”

Key Concept

In a nutshell, expected counts are what we anticipate seeing in each category if the null hypothesis is true. Think of it as the baseline we're comparing our actual results against.

  • Null Hypothesis: This is the assumption we're testing โ€“ usually, it states there's no difference or relationship between variables.
  • Calculation: Expected Count = (Sample Size) x (Probability under Null Hypothesis)
    • Example: If you survey 100 people and expect a 50/50 split, the expected count for each category is 50. * Why they matter: They help us determine if our observed data is significantly different from what we'd expect by chance.

Chi-Square Statistic: Measuring the Difference ๐Ÿ“

The chi-square statistic quantifies how much our observed data deviates from our expected counts.

  • Formula: ฯ‡2=โˆ‘(Observedโˆ’Expected)2Expected\chi^2 = \sum \frac{(Observed - Expected)^2}{Expected}
    • We sum the squared differences between observed and expected counts, divided by the expected counts, for each category.
  • Interpretation:
    • A large chi-square value means a big difference between observed and expected, suggesting the null hypothesis might be false.
    • A small chi-square value suggests the observed data is close to what's expected under the null hypothesis.
  • P-value: We use the chi-square statistic to calculate a p-value, which tells us the probability of getting our observed results (or more extreme) if the null hypothesis were true.
    • A small p-value (typically < 0.05) means our results are statistically significant, and we reject the null hypothesis.

Chi-Square Distributions: The Shape of Things ๐Ÿ“Š

Quick Fact

Chi-square distributions are always positive and skewed to the right.

  • Degrees of Freedom (df): This parameter determines the shape of the distribution.
    • df = (Number of Categories) - 1
    • As df increases, the distribution becomes more symmetrical.
  • Visual: Chi-Square Distribution
    • Caption: Notice how the distribution is skewed right, but becomes more symmetrical as degrees of freedom increase.

Goodness of Fit Test: Does It Fit? ๐ŸŽฏ

The chi-square goodness of fit (GOF) test checks if the observed frequencies of a categorical variable match a hypothesized distribution.

  • Use Case: When you have one categorical variable with more than two categories and want to see if the observed data matches a specific distribution.
  • Example: Checking if the distribution of favorite colors in a sample matches the expected distribution.
  • Parameters: Population proportions for each category.
    • Example: If you have a claim that 10% prefer blue, 20% prefer green, and 70% prefer red, your parameters are the true proportions for each color.
  • Hypotheses:
    • Null Hypothesis (H0): The observed distribution matches the claimed distribution.
    • Alternative Hypothesis (Ha): At least one of the proportions in the null hypothesis is incorrect.
    • Context is Key: Always define your parameters and use subscripts to show which proportion refers to which category.

Conditions for GOF Test

Exam Tip

Always remember to check these conditions! It's an easy way to earn points on the FRQ.

  • Random: The sample must be randomly selected.
  • Independence: The population must be at least 10 times the sample size (10% rule).
  • Large Counts: All expected counts must be at least 5. ## Example: Movie Series Preference ๐ŸŽฌ

Let's revisit the example from the notes. A survey claims that people are equally likely to prefer Harry Potter, Lord of the Rings, or Star Wars. We want to test this claim using a sample of 2500 US adults.

Hypotheses and Parameters

  • H0: pHP = 0.33, pSW = 0.33, pLOTR = 0.33
    • (where pHP, pSW, and pLOTR are the true proportions of people who prefer each series)
  • Ha: At least one of the proportions of favorite movie/book series is incorrect.

Conditions

  • Random: "A random sample of 2500 US adults" (quoted from the problem).
  • Independence: It's reasonable to assume there are at least 25,000 adults in the US (10% rule).
  • Large Counts: 2500 * 0.33 = 825 > 5 (this holds true for all three categories).
Memory Aid

Remember RIL for conditions: Random, Independence, Large Counts.

Final Exam Focus ๐ŸŽฏ

Chi-square tests are a high-value topic on the AP exam, often appearing in both multiple-choice and free-response questions.

  • Key Concepts:
    • Understanding the difference between observed and expected counts.
    • Calculating the chi-square statistic.
    • Interpreting the p-value in context.
    • Checking conditions for inference.
  • Common Question Types:
    • Hypothesis testing using chi-square GOF.
    • Interpreting chi-square output from statistical software.
    • Identifying the correct test to use based on the scenario.
  • Exam Tips:
    • Always state your hypotheses in context.
    • Show your work when calculating expected counts and the chi-square statistic.
    • Clearly explain your conclusions based on the p-value.
    • Pay attention to the wording of the question to determine if it's a GOF test.
  • Time Management:
    • Practice identifying key information quickly.
    • Don't spend too much time on one question.
    • If you get stuck, move on and come back later if you have time.
  • Common Mistakes:
    • Forgetting to check conditions.
    • Incorrectly calculating expected counts.
    • Misinterpreting the p-value.
    • Not providing context in hypotheses and conclusions.

Practice Questions ๐Ÿ“

Let's put your knowledge to the test with some practice questions!

Practice Question

Multiple Choice Questions

  1. A researcher is testing if a die is fair. They roll the die 60 times and record the number of times each face appears. What statistical test is most appropriate for this situation? (A) One-sample t-test (B) Two-sample t-test (C) Chi-square goodness-of-fit test (D) Linear regression t-test (E) One-proportion z-test

  2. In a chi-square goodness-of-fit test, what does a large chi-square statistic indicate? (A) The observed counts are very close to the expected counts. (B) The observed counts are very different from the expected counts. (C) The sample size is too small. (D) The null hypothesis is likely true. (E) The p-value is large.

  3. A company claims that the distribution of colors in their candy bags is 20% red, 30% blue, 25% green, and 25% yellow. A student buys a bag and counts the colors. What is the null hypothesis for a chi-square goodness-of-fit test in this scenario? (A) The true proportions of colors are all equal. (B) At least one of the proportions of colors is incorrect. (C) The true proportions of colors are 20% red, 30% blue, 25% green, and 25% yellow. (D) The true proportions of colors are different from the claimed proportions. (E) The true proportions of colors are less than the claimed proportions.

Free Response Question

A survey was conducted to determine the preferred type of music among teenagers. A random sample of 500 teenagers was asked whether they prefer pop, rock, or hip-hop music. The results are summarized below:

Music TypeObserved Count
Pop180
Rock150
Hip-Hop170

The music distributor claims that the distribution of music preference among teenagers is 40% pop, 30% rock, and 30% hip-hop.

(a) State the null and alternative hypotheses for this test. (b) Calculate the expected counts for each music type. (c) Calculate the chi-square test statistic. (d) Calculate the degrees of freedom. (e) What conclusion would you make with a significance level of 0.05?

Scoring Rubric

(a) Hypotheses (2 points)

  • 1 point for stating the null hypothesis correctly with context:
    • H0: The true proportions of music preference among teenagers are 40% pop, 30% rock, and 30% hip-hop.
  • 1 point for stating the alternative hypothesis correctly with context:
    • Ha: At least one of the true proportions of music preference among teenagers is incorrect.

(b) Expected Counts (3 points)

  • 1 point for each correct expected count:
    • Pop: 500 * 0.40 = 200
    • Rock: 500 * 0.30 = 150
    • Hip-Hop: 500 * 0.30 = 150

(c) Chi-Square Statistic (3 points)

  • 1 point for showing the correct formula:
    • ฯ‡2=โˆ‘(Observedโˆ’Expected)2Expected\chi^2 = \sum \frac{(Observed - Expected)^2}{Expected}
  • 1 point for correctly plugging in the values:
    • ฯ‡2=(180โˆ’200)2200+(150โˆ’150)2150+(170โˆ’150)2150\chi^2 = \frac{(180-200)^2}{200} + \frac{(150-150)^2}{150} + \frac{(170-150)^2}{150}
  • 1 point for the correct calculation:
    • ฯ‡2=2+0+2.67=4.67\chi^2 = 2 + 0 + 2.67 = 4.67

(d) Degrees of Freedom (1 point)

  • 1 point for correctly stating the degrees of freedom:
    • df = 3 - 1 = 2

(e) Conclusion (2 points)

  • 1 point for comparing the p-value to the significance level:
    • The p-value for a chi-square statistic of 4.67 with 2 degrees of freedom is approximately 0.097. * Since 0.097 > 0.05, we fail to reject the null hypothesis.
  • 1 point for stating the conclusion in context:
    • There is not sufficient evidence to conclude that the distribution of music preference among teenagers is different from the music distributor's claim.

You've got this! Keep reviewing, stay confident, and go crush that AP Stats exam! ๐Ÿ’ช