Hardy-Weinberg Equilibrium

Mia Gonzalez
7 min read
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Study Guide Overview
This study guide covers the Hardy-Weinberg Equilibrium, including its underlying assumptions (no mutation, no selection, no gene flow, infinite population size, random mating), the equations for calculating allele and genotype frequencies (p + q = 1 and p² + 2pq + q² = 1), and how to apply these equations through example problems. It emphasizes the importance of Hardy-Weinberg as a null hypothesis for evolution and connects it to other evolutionary mechanisms. The guide also provides tips for the AP Biology exam, focusing on understanding the conditions, mastering the equations, and applying the concept. Practice questions and a scoring breakdown are included.
#AP Biology: Hardy-Weinberg Equilibrium - Your Last-Minute Guide 🚀
Hey there, future AP Bio rockstar! Let's break down Hardy-Weinberg, a key concept that might seem tricky but is totally manageable. We'll make sure you're feeling confident and ready to tackle any question on this topic. Let's get started! 💪
#Introduction to Hardy-Weinberg Equilibrium
The Hardy-Weinberg equilibrium is a model that describes a theoretical state where allele frequencies in a population remain constant from generation to generation. Think of it as a baseline to compare real-world populations against. If a population deviates from this equilibrium, it suggests that evolution is occurring! 💡
#Key Assumptions
This model operates under five crucial assumptions. Remember, these are rarely (if ever) met in nature, but they're essential for the model to work:
- No Mutation: 🧬 No new alleles are popping up. The existing ones are simply passed down.
- No Selection: 🎯 No allele has an advantage. Natural or artificial selection isn't playing favorites.
- No Gene Flow: 🚶♀️ No migration or movement of individuals in or out of the population. No new alleles entering or leaving.
- Infinite Population Size: ♾️ The population is huge, so random fluctuations in allele frequencies (genetic drift) are negligible.
- Random Mating: 💘 Mating is random, with no preference for certain genotypes.
These conditions are almost impossible in real life, but they help us understand how populations change when these conditions are not met. This is why Hardy-Weinberg acts as a null hypothesis for evolution.
Don't forget that Hardy-Weinberg is a model, not a real-world situation. It's a theoretical baseline to show how evolution might be occurring. This is a common point where students lose marks.
#Understanding the Equations
Okay, let's talk equations. Don't panic! They're not as scary as they look. We have two main equations:
-
Allele Frequencies:
p
= frequency of the dominant alleleq
= frequency of the recessive allele
-
Genotype Frequencies:
- = frequency of homozygous dominant genotype
- = frequency of heterozygous genotype
- = frequency of homozygous recessive genotype
#How to Use Them
- Find
q²
: Start with the homozygous recessive phenotype. This is the only genotype directly observable from the phenotype. - Calculate
q
: Take the square root ofq²
. - Calculate
p
: Usep = 1 - q
. - Plug and Play: Use
p
andq
in the second equation to find genotype frequencies.
Think of it like a puzzle: find the missing piece (q
), then use it to solve the rest. Start with what you know (recessive phenotype) and work your way through the rest of the equation. This will help you remember the sequence.
#Visual Aid
Remember, p
and q
are allele frequencies, while p²
, 2pq
, and q²
are genotype frequencies. Don't mix them up!
#Example Walkthrough
Let's make it concrete with an example:
Imagine a bird population where 84 out of 100 birds have white feathers (dominant), and 16 have grey feathers (recessive). Here's how we solve it:
q²
: 16/100 = 0.16 (frequency of grey birds)q
: √0.16 = 0.4 (frequency of the recessive allele)p
: 1 - 0.4 = 0.6 (frequency of the dominant allele)p²
: 0.6² = 0.36 (frequency of homozygous dominant birds)2pq
: 2 * 0.6 * 0.4 = 0.48 (frequency of heterozygous birds)
#Example Problem and Explanation
Let's tackle a more complex problem:
Problem: A rare genetic disorder is caused by a recessive allele, "a", with a frequency of 0.02. Calculate the frequencies of the dominant allele "A", homozygous recessive (aa), and heterozygous (Aa) individuals. Also, list the assumptions made in this scenario.
Solution:
- Assign variables:
q
= frequency of "a" = 0.02,p
= frequency of "A" - Calculate
p
:p = 1 - q = 1 - 0.02 = 0.98
- Calculate
q²
:q² = 0.02² = 0.0004
(0.04% homozygous recessive) - Calculate
2pq
:2pq = 2 * 0.98 * 0.02 = 0.0392
(3.92% heterozygous)
Assumptions:
- No mutation
- No selection
- No gene flow
- Infinite population size
- Random mating
Always state the assumptions when asked in a free-response question. It shows you understand the limitations of the model.
#Final Exam Focus
Alright, let's focus on what's most important for the exam:
- Understand the conditions: Know why each condition is essential for Hardy-Weinberg equilibrium.
- Master the equations: Practice using the equations to solve for allele and genotype frequencies. Focus on starting with
q²
. - Apply the concept: Understand that Hardy-Weinberg is a null hypothesis. Deviations from the equilibrium indicate evolution.
- Connect to other units: Relate Hardy-Weinberg to natural selection, genetic drift, and other evolutionary mechanisms.
#Last-Minute Tips
- Time Management: Start with the easier parts of the problem, like finding
q²
. Then, work your way top
and2pq
. - Common Pitfalls: Don't mix up allele and genotype frequencies. Always double-check your calculations.
- FRQ Strategy: Clearly state your assumptions and show all your work. Even if you make a mistake, you might get partial credit for the correct process.
Practice, practice, practice! The more you work through problems, the more comfortable you will be with the calculations and concepts. Focus on understanding the process, not just memorizing the formulas.
#Practice Questions
Okay, let's test your knowledge with some practice questions:
Practice Question
Multiple Choice Questions:
-
In a population of butterflies, the allele for black wings (B) is dominant over the allele for white wings (b). If 16% of the butterflies in a population are white, what is the frequency of the black wing allele? (A) 0.16 (B) 0.36 (C) 0.4 (D) 0.6
-
Which of the following conditions is NOT an assumption of the Hardy-Weinberg equilibrium? (A) No mutation (B) Random mating (C) Small population size (D) No gene flow
Free Response Question:
In a population of 500 pea plants, 320 have purple flowers (dominant), and 180 have white flowers (recessive). Assume that the population is in Hardy-Weinberg equilibrium.
(a) Calculate the frequencies of the dominant and recessive alleles. (b) Calculate the number of plants that are homozygous dominant, heterozygous, and homozygous recessive. (c) Explain how a change in the environment that favors white flowers would affect the allele frequencies in the next generation.
Scoring Breakdown:
(a) 3 points * 1 point for calculating q² correctly (180/500 = 0.36) * 1 point for calculating q correctly (√0.36 = 0.6) * 1 point for calculating p correctly (1 - 0.6 = 0.4)
(b) 3 points * 1 point for calculating p² correctly (0.4² = 0.16), and multiplying by 500 (80 plants) * 1 point for calculating 2pq correctly (2 * 0.4 * 0.6 = 0.48), and multiplying by 500 (240 plants) * 1 point for stating the number of homozygous recessive plants (180 plants)
(c) 3 points * 1 point for stating that the frequency of the recessive allele would increase * 1 point for stating that the frequency of the dominant allele would decrease * 1 point for explaining that natural selection is favoring the recessive allele
You've got this! Go ace that exam! 🎉

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